padders
38 = A 'A' being the about of symbols
6 = B 'B' being the usable amount of chevrons in a 7 chevron coordinate
which gives the formula of AxB=C where C being the sum of A and B.
so that's 38x6 which is 228
then for a 8 chevron coordinate you have to multiply
228 by 7 with 7 being the usable chevrons.
unfortunatly not the way to do it:
for example:
imagine there were only 5 symbols and you needed to pick 3 of them.
You would say there would be 15 combination i assume yet there are a lot more:
say pick 3 from 1 2 3 4 5:
123
124
125
132
134
135
142
143
145
152
153
154
212
213
214
215
and i can go on..
you see, you do NOT multiply the number of what you are choosing from by the number you have to choose.
Think about a bank pin of 4 numbers. If your logic was the case there would only be 10x4 options = 40! not very good.
MythingLink : it would not be infinite, it would actually only be about 1 order of magnitude greater.
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Chris Padfield, administrator for TalkStargate.com
http://www.talkstargate.com/ - Talk Stargate till your heart's content!